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A ball is thrown at different angles with the same speed Vo from the same point on ground and it has same range in both cases. If the sum of maximum heights attained by the ball is 90m and g=10m/s2, find Vo

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Detailed Solution

If angle of projection in one case is α, angle of projection in the other case is(90o−α)∴H1=V02sin2α2g and H2=V02sin2(90o−α)2g=V02cos2α2g∴H1+ H2=V022g⇒V0=2g(H1+ H2)=2×10×90 m/s=302 m/s

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