First slide

Projection Under uniform Acceleration

Question

A ball thrown down the incline strikes at a point on the incline 25 m below the horizontal as shown in the figure. If the ball rises to a maximum height of 20 m above the point of projection, the angle of projection a (with horizontal x axis) is

Moderate

A

$\tan^{- 1} \frac{4}{3}$
B

$\tan^{- 1} \frac{3}{4}$
C

$\tan^{- 1} \frac{3}{2}$
D

$\tan^{- 1} \frac{2}{3}$

Solution

$20 = \frac{u^{2} \sin^{2} x}{2 g} \Rightarrow u \sin α = 20$
$- 25 = 20 t - \frac{1}{2} 10 t^{2} \Rightarrow t = 5 s$
75 = (u cos $α$ )t
Solve to get $\tan α = \frac{4}{3}$

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