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Q.

A ball is thrown from ground at angle  θ with horizontal and with an initial speed u0. For the resulting projectile motion, the magnitude of average velocity of the ball up to the point when it hits the ground for the first time is V1. After hitting the ground, the ball rebounds at the same angle θ  but with a reduced speed of u0/α . Its motion continues for a long time as shown in figure. If the magnitude of average velocity of the ball for entire duration of motion is 0.8 V1, the value of α  is _____

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answer is 4.00.

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Detailed Solution

R1=u02sin⁡2θgR2=1α2u02sin⁡2θg=R1a2 Total Range =R=R1+R1a2+…=R111−1a2=R1a2a2−1t1=2u0sin⁡θgt2=t1α…… Total time of flight =T=t1+t2+…..=t111−1a=αt1α−1 Given : Average velocity =R1t1=v1 Total Average velocity =RT=R1a2a2−1at1a−1=R1t1×αα+1 Given :R1t1×αα+1=0.8R1t1⇒α=4
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