Questions
A ball is thrown from the ground to a wall 3 m high at a distance of 6 m . If the ball just clears the wall and falls 18 m away from the wall, the angle of projection of ball is
detailed solution
Correct option is B
Here, R=u2sin2θg=24∵ y=xtanθ-gx22u2cos2θ 3=6tanθ-36g2u2cos2θ …(ii)From Eq. (i), we get gu2=sin2θ24=sinθcosθ12Substituting in Eq. (ii), we get 3=6tanθ-32tanθ=92tanθ⇒θ=tan-123Talk to our academic expert!
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A ball is thrown with a velocity of u making an angle with the horizontal. Its velocity vector normal to initial vector (u) after a time interval of
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