First slide

Projection Under uniform Acceleration

Question

A ball is thrown from the top of 36 m high tower with velocity 5 m/s at an angle 37° above the horizontal as shown. Its horizontal distance on the ground is closest to : [g = 10m/s²]

Moderate

A

12 m
B

18 m
C

24m
D

30m

Solution

By using. $s = ut + \frac{1}{2} {at}^{2}$ in vertical direction
-36 = 3t - 5t²
=t = 3s
Range = (5cos37°) t = (4). 3 = 12m

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