A ball is thrown from the top of a tower with an initial velocity of $$10$$ $$ms-1$$ at an angle of $$30o$$ with the horizontal. If it hits the ground at a distance of $$17.3$$ m from the back of the tower, the height of the tower is (Take$$ g: $$10$$ $$ms-2)

Question

A ball is thrown from the top of a tower with an initial velocity of $$10$$ $$ms-1$$ at an angle of $$30o$$ with the horizontal. If it hits the ground at a distance of $$17.3$$ m from the back of the tower, the height of the tower is (Take$$ g: $$10$$ $$ms-2)

Infinity Learn · Accepted Answer

Here, θ$$=$$ $$30o$$, u $$=$$ $$10$$ $$ms-1$$,           R $$=$$ $$17.3$$ m, g $$=$$ $$10$$ $$ms-2For$$ horizontal motion, R $$=$$ u $$cos$$ θtt $$=$$ Ru $$cos$$ θ $$=$$ $$17.310$$ $$cos$$ $$300$$ $$=$$ $$17.3$$ ×$$210$$×$$3$$ $$=$$ $$17.3$$×$$210$$×$$1.73$$ $$=$$ $$2$$ sFor vertical motion, h $$=$$ u $$sin$$ θt $$=$$ $$12gt2$$ $$=$$ $$10$$ $$sin$$ $$300$$×$$2-12$$×$$10$$×$$22=$$ $$10-20$$ $$=$$ $$-10$$ m.Height of tower $$=$$ $$10$$ m.

A ball is thrown from the top of a tower with an initial velocity of 10 ${ms}^{- 1}$ at an angle of $30^{o}$ with the horizontal. If it hits the ground at a distance of 17.3 m from the back of the tower, the height of the tower is (Take g: 10 ${ms}^{- 2}$ )

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A ball is thrown from the top of a tower with an initial velocity of 10 ms-1 at an angle of 30o with the horizontal. If it hits the ground at a distance of 17.3 m from the back of the tower, the height of the tower is (Take g: 10 ms-2)

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A ball is thrown from the top of a tower with an initial velocity of 10 ${ms}^{- 1}$ at an angle of $30^{o}$ with the horizontal. If it hits the ground at a distance of 17.3 m from the back of the tower, the height of the tower is (Take g: 10 ${ms}^{- 2}$ )