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Q.

A ball thrown horizontally with a velocity of 8 m/s from the top of the building strikes the ground 12m away from the building. What is the height of the building? (g=9.8 m/s2)

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a

11 m

b

10 m

c

8 m

d

7 m

answer is A.

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Detailed Solution

given initial velocity horizontally = ux=8 m/s; Range = R=12mR=Ut⇒t=RUt=128 Now height of building= h=12gt2h=12(9.8)1282=11.25m
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