A ball is thrown straight upward with a velocity v0 from a height h above the ground. The time taken for the ball to strike the ground is

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v0g1+2ghv02

v0g1−1+2ghv02

v0g1+1+2ghv02

answer is D.

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Detailed Solution

Apply s=ut+12at2⇒ −h=v0t−12gt2⇒gt2−2v0t−2h=0⇒ t=2v0±4v02+8gh2gAs t is not negative, so ignoring negative sign, we gett=2v0+2v02+2gh2g=v0g1+1+2ghv02

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