A ball is thrown upwards with a speed of 40 m/s. When the speed becomes half of the initial speed, gravity is switched off for next 2 second. After that gravity is again switched on but magnitude of gravity is doubled. The total distance travelled by the ball from t = 0 to the time when the ball reaches the maximum height (in m) isTake g=10 ms-2

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answer is 110.

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Detailed Solution

Speed will remain half or 20 msafter 2 s.d1=ut+12at2=40×2-12×10×(2)2=60 md2=vt=20×2=40 md3=v22g'=(20)22×20=10 m ∴d=d1+d2+d3=110 m

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