First slide
The 3 equation for uniform acc
Question

A ball is thrown vertically downward with a velocity of 20 m/s from the top of a tower. It hits the ground after some time with a velocity of 80 m/s. The height of the tower is (Take, g = 10 m/s2 )   [NEET 2020]

Moderate
Solution

Given, u = 20 m/s, v = 80 m/s and h = ?
From kinematic equation of motion, v2 = u2 + 2gh

h=v2-u22g=(80)2-(20)22×10            ( Given, g = 10 m/s2)

        = 300 m

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