First slide

Vertical projection from top of a tower

Question

A ball is thrown vertically downward with a velocity of 20 m/s from the top of a tower. It hits the ground after some time with a velocity of 80 m/s. The height of the tower is :( g=10 $m / s^{2}$ )

Easy

Solution

$\begin{array}{l} v^{2} - u^{2} = 2 as \\ 80^{2} - 20^{2} = 2 \times 10 \times h \\ h = \frac{100 \times 60}{20} = 300 m \end{array}$

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