First slide

Vertical projection from ground

Question

A ball is thrown vertically upward. It has a speed of 10 m/s when it has reached one half of its maximum height. How high does the ball rise ? Tiake g = 10 m/s²

Easy

A

5 m
B

10 m
C

15 m
D

20 m

Solution

The situation is shown in figure
For part CB, we have
u =10 m/s² and v=0
Now v² = u² -2gs
$∴$ 0 = (10)² -2x10x(h/2)
or 10h =100 or h=10m

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