Banner 0
Banner 1
Banner 2
Banner 3
Banner 4
Banner 5
Banner 6
Banner 7
Banner 8
Banner 9

Q.

A ball thrown vertically upwards after reaching a maximum height h returns to the starting point aftera time of 10s. Its displacement after 5 s is

see full answer

High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET

🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya

a

h

b

2h

c

10h

d

20h

answer is A.

(Unlock A.I Detailed Solution for FREE)

Best Courses for You

JEE

JEE

NEET

NEET

Foundation JEE

Foundation JEE

Foundation NEET

Foundation NEET

CBSE

CBSE

Detailed Solution

The position of an object is always expressed w.r.t. some reference point. If the initial position of an object w.r.t. a reference points is s1 and after sometime, it changes to s2, then the magnitude of the displacement of the object is s2 - s1. Since, the given ball returns to its starting point in 10s. So, in 5s, it reaches the highest point which is at s2.Given, s2 is at a height h w.r.t. s1. Thus, the displacement after 5s will be s2 - s1 = h.
Watch 3-min video & get full concept clarity

courses

No courses found

score_test_img

Get Expert Academic Guidance – Connect with a Counselor Today!

whats app icon