Q.
A ball is thrown vertically upwards with some speed. It reaches two points A and B one after another such that heights of A and B are one fourth and three-fourth of the maximum height attained. If the total time of flight is T, the maximum time taken by the ball to travel from A to B, is :
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a
3+14T
b
3−12T
c
3+12T
d
T2
answer is A.
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Detailed Solution
T=22hg⇒2hg=T2Maximum time between A to B is = tAO + tOB=2h4g+23h4g=T212+32=T(3+1)4
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