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Q.

A ball is thrown vertically upwards with a speed $u$. It reaches a point B at a height h (lower than the maximum height) after time t1. It returns to the ground after time t2 from the instant it was at B during the upward journey. Then, t1t2 is equal to

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a

2 h / g

b

h/g

c

h/2g

d

h/4 g

answer is A.

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Detailed Solution

Total time of jouney is t1+t2Therefore, 2ug=t1+t2Further,h=ut1-12gt12  or h=gt1+t2t12-12gt12  or   gt2=2h ∴  t1t2=2hg
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