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Questions  

A ball is thrown vertically upwards with a speed $u$. It reaches a point B at a height h (lower than the maximum height) after time t1. It returns to the ground after time t2 from the instant it was at B during the upward journey. Then, t1t2 is equal to

a
2 h / g
b
h/g
c
h/2g
d
h/4 g

detailed solution

Correct option is A

Total time of jouney is t1+t2Therefore, 2ug=t1+t2Further,h=ut1-12gt12  or h=gt1+t2t12-12gt12  or   gt2=2h ∴  t1t2=2hg

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