A ball is thrown vertically upwards with a speed $u$. It reaches a point B at a height h (lower than the maximum height) after time t1. It returns to the ground after time t2 from the instant it was at B during the upward journey. Then, t1t2 is equal to
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a
2 h / g
b
h/g
c
h/2g
d
h/4 g
answer is A.
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Detailed Solution
Total time of jouney is t1+t2Therefore, 2ug=t1+t2Further,h=ut1-12gt12 or h=gt1+t2t12-12gt12 or gt2=2h ∴ t1t2=2hg