Questions
A ball weighing 10 g hits a hard surface vertically with a speed of 5 m/s and rebounds with the same speed. The ball remains in contact with the surface for 0.01 sec. The average force exerted by the surface on the ball is:
detailed solution
Correct option is B
Fav=ΔpΔt=10×10−3(5+5)0.01=10NTalk to our academic expert!
Similar Questions
Figures I, II, III and IV depict variation of force with time. Select the figure(s) that depicts minimum impulse delivered.
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