A ball of weight 0.1 kg coming with speed 30 m/s strikes with a bat and returns in opposite direction with speed 40 m/s, then the impulse is (Taking final velocity as positive)
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a
−0.1×(40)−0.1×(30)
b
0.1×(40)−0.1×(−30)
c
0.1×(40)+0.1×(−30)
d
0.1×(40)−0.1×(20)
answer is B.
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Detailed Solution
Impulse = change in momentum mv2−mv1=0.1×40−0.1×(−30)