A ballet dancer, dancing on a smooth floor is spinning about a vertical axis with her arms folded with angular velocity of 20 rad/s. When she stretches her arms fully, the spinning speed decreases to l0 rad/s. If I is the initial moment of inertia of the dancer, the new moment of inertia is
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a
2l
b
3l
c
I2
d
I3
answer is A.
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Detailed Solution
Here, angular momentum is conserved.Initial angular momentum: Final angular momentum I × 20 = I'×10Where 1 is new moment of inertia I' = 2I