Q.

A balll is projected with 20√2 m/s at angle 450 with horizontal. The angular velocity of the particle at highest point of its journey about point of projection is

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answer is 2.

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Detailed Solution

r2 = (40)2 +(20)2 = (20)2 (5) m2
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A balll is projected with 20√2 m/s at angle 450 with horizontal. The angular velocity of the particle at highest point of its journey about point of projection is