Q.

A balloon has 8 g of air. A small hole is pierced into it. The air escapes at a uniform rate of 7 cm/s. If the balloon shrinks in 5 .6 second, then the average force acting on the balloon is

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a

10-4 N

b

10-2 dyne

c

56 dyne

d

10-6 N

answer is A.

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Detailed Solution

The rate of change of momentum =V×dmdt∴ Average force =7100×(8/1000)(5⋅6)=10−4N
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A balloon has 8 g of air. A small hole is pierced into it. The air escapes at a uniform rate of 7 cm/s. If the balloon shrinks in 5 .6 second, then the average force acting on the balloon is