A balloon rises from rest on the ground with constant acceleration 1.25 m s-2. A stone is dropped when the balloon has risen to a height of 40 m. Find the time ( in sec) taken by the stone to reach the ground.

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answer is 4.

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Detailed Solution

h=12at2⇒t=2ha=2×40×810=8sVelocity after 8 s, v=0+1.25×8=10ms−140=−10t+1210t210t2-2×10t-2×40=0t2−2t−8=0t−4t+2t−8=0t=4s

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