Q.

a balloon is rising vertically up with a velocity of 29ms−1 . A stone dropped from it and it reaches the ground in 10s . The height of the balloon when the stone was dropped from it is (g=9.8ms−2)

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a

400m

b

150m

c

100m

d

200m

answer is D.

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Detailed Solution

Taking vertical downward motion of the stone released from the balloon going up, we have u=−29m/s;a=9.8m/s2,t=10 and s=?  Nows=ut+12at2 =−29×10+12×9.8×102  =−290+490=200m
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