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Questions  

A balloon starting from rest ascends vertically with uniform acceleration to a height of 100 m in 10 s. The force on the bottom of the balloon by a mass of 50 kg is (Take, g = 10 ms-2)       [EAMCET 2013]

a
100 N
b
300 N
c
600 N
d
400 N

detailed solution

Correct option is C

Given, h = 100 m and t = 10 sFrom second equation of motion,  h = 12at2⇒  a=2ht2=2×100(10)2=2 ms-2Now,  F=m(g+a)=50(10+2)=600 N

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