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Q.

A balloon starting from rest ascends vertically with uniform acceleration to a height of 100 m in 10 s. The force on the bottom of the balloon by a mass of 50 kg is (Take, g = 10 ms-2)       [EAMCET 2013]

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a

100 N

b

300 N

c

600 N

d

400 N

answer is C.

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Detailed Solution

Given, h = 100 m and t = 10 sFrom second equation of motion,  h = 12at2⇒  a=2ht2=2×100(10)2=2 ms-2Now,  F=m(g+a)=50(10+2)=600 N
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