First slide

Instantaneous acceleration

Question

A balloon starts rising from the ground with an acceleration of 1.25 m/s². After 8s, stone is released from the balloon. The stone will (Taking g = 10 ms^–2)

Easy

A

begin to move down after being released
B

reach the ground in 4s
C

cover a distance of 40m before reaching the ground
D

will have a displacement of 50m

Solution

Velocity after 8 sec, v = at = 1.25 x 8 = 10 m/ s
height after 8 sec, $h = \frac{1}{2} {at}^{2} = 40 m$
Solving $h = - vt + \frac{1}{2} {gt}^{2}$
$40 = - 10 t + \frac{1}{2} 10 t^{2}$
t = 4 sec.

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