A balloon starts rising from the ground with an acceleration of 1.25 m/s2. After 8s, stone is released from the balloon. The stone will (Taking g = 10 ms–2)

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begin to move down after being released

reach the ground in 4s

cover a distance of 40m before reaching the ground

will have a displacement of 50m

answer is B.

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Detailed Solution

Velocity after 8 sec, v = at = 1.25 x 8 = 10 m/ sheight after 8 sec, h=12at2=40mSolving h=−vt+12gt240=−10t+1210t2t = 4 sec.

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