A balloon starts rising from the ground with an acceleration of 1.25 m/s2. After 8s, stone is released from the balloon. The stone will (Taking g = 10 ms–2)

see full answer

Talk to JEE/NEET 2025 Toppers - Learn What Actually Works!

Real Strategies. Real People. Real Success Stories - Just 1 call away

An Intiative by Sri Chaitanya

begin to move down after being released

reach the ground in 4s

cover a distance of 40m before reaching the ground

will have a displacement of 50m

answer is B.

(Unlock A.I Detailed Solution for FREE)

Ready to Test Your Skills?

Check your Performance Today with our Free Mock Test used by Toppers!

Take Free Test

Detailed Solution

Velocity after 8 sec, v = at = 1.25 x 8 = 10 m/ sheight after 8 sec, h=12at2=40mSolving h=−vt+12gt240=−10t+1210t2t = 4 sec.

Watch 3-min video & get full concept clarity