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Questions  

A balloon with mass m is descending down with an acceleration a (where, a < g). How much mass should be removed from it, so that it starts moving up with an acceleration a?    

a
2 mag + a
b
2 mag - a
c
mag + a
d
mag - a

detailed solution

Correct option is A

When the balloon is descending down with acceleration a,mg - B = m × a       .....(i)where, B = Buoyant force.Here, we should assume that while removing some mass, the volume of balloon and hence, buoyant force will not change.Let the new mass of the balloon is m'.So, mass removed = m - m'When the balloon is moving up with acceleration a, thenB - m'g = m' × a       .....(ii)Adding Eqs. (i) and (ii), we get⇒  mg-m'g=ma+m'a⇒  (mg-ma)=m'(g+a)⇒  m(g-a)=m'(g+a)∴  m'=m(g-a)(g+a)So, mass removed,Δm=m-m'=m1-(g-a)(g+a)=m(g+a)-(g-a)(g+a)=mg+a-g+ag+a=2mag+a

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Similar Questions

Statement I : The familiar equation mg = R for a body on a table is true only if the body is in equilibrium.

Statement II : The equality of mg and R has no connection with the third law.


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