Q.
A bar magnet is held perpendicular to a uniform magnetic field if the couple acting on the magnet is to be halved by rotating it, then the angle by which it is to be rotated is
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a
30o
b
45o
c
60o
d
90o
answer is C.
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Detailed Solution
τ=MBsinθ ⇒τ∝sinθ ⇒τ1τ2=sinθ1sinθ2 ⇒ττ2=sin90sinθ2 ⇒sinθ2=12 ⇒θ2=300 So, bar magnet should be rotated by 600.
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