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Questions  

A bar magnet of length 10 cm and having the pole strength equal to 10–3 weber is kept in a magnetic field having magnetic induction (B) equal to 4π×103 Tesla. It makes an angle of 30o with the direction of magnetic induction. The value of the torque acting on the magnet is

μ0=4π×107weber/amp×m

a
2π×10−7N×m
b
2π×10−5N×m
c
0.5N×m
d
0.5×102N×m

detailed solution

Correct option is A

Torque τ=MBHsinθ=0.1×10−3×4π×10−3×sin⁡30∘=10−7×4π×12=2π×10−7N×m

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