First slide

Magnetism

Question

A bar magnet of length 0.1m has a pole strength of 50Am. The magnetic field at a distance of 0.2m from its centre on its equatorial line

Moderate

A

$4 \times 10^{- 5} T$
B

$2.7 \times 10^{- 5} T$
C

$5.7 \times 10^{- 5} T$
D

$5.7 \times 10^{- 6} T$

Solution

Magnetic field induction at a point on its equatorial line is
$B = \frac{μ_{0}}{4 π} \frac{M}{{(d^{2} + l^{2})}^{\frac{3}{2}}} \Rightarrow B = \frac{μ_{0}}{4 π} \frac{m (2 l)}{{(d^{2} + l^{2})}^{\frac{3}{2}}} \Rightarrow B = \frac{10^{- 7}}{1} \times \frac{(50) (0.1)}{{[{(0.2)}^{2} + {(0.05)}^{2}]}^{\frac{3}{2}}} \Rightarrow B = 5.7 \times 10^{- 5} T$

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