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Q.

A bar magnet of length 0.1m has a pole strength of 50Am. The magnetic field at a distance of 0.2m from its centre on its equatorial line

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a

4×10−5T

b

2.7×10−5T

c

5.7×10−5T

d

5.7×10−6T

answer is C.

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Detailed Solution

Magnetic field induction at a point on its equatorial line is                                            B=μ04πMd2+l232 ⇒B=μ04πm(2l)d2+l232 ⇒B=10−71×(50)(0.1)(0.2)2+(0.05)232 ⇒B=5.7×10−5T
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