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A bar magnet of magnetic moment 10 Am2 has a cross sectional area of 2.5 × 10–4 m2. If the intensity of magnetization of the magnet is 106 A/m, then the length of magnet is

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answer is 3.

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Detailed Solution

I=MlA ; l=10106 x 2.5 x 10-4=0.04 m

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