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A bar magnet of magnetic moment 10 Am2 has a cross sectional area of 2.5×10−4 m2. If the intensity of magnetization of the magnet is 106 A/m, the length of magnet is

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a

0.4m

b

0.04cm

c

0.04m

d

40 cm

answer is C.

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Detailed Solution

GivenMagnetic moment M=10 Am2Cross sectional Area A=2.5×10−4 m2∴ Intensity of magnetization I=MV∵V=ALI=MAL⇒I=102.5×10−4×L⇒L=102.5×10−4×106∴L=4×10−2 m

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