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Questions  

A bar magnet of magnetic moment 3.0 Am2 is placed in a uniform magnetic induction field of 2 x 10-5 T. If each pole of the magnet experiences a force of 6 x 10-4N. The length of the magnet is

a
0.5 m
b
0.3 m
c
0.2 m
d
0.1 m

detailed solution

Correct option is D

F=mB⇒F=MLx B⇒6 x 10-4=3 L x 2 x 10-5 ⇒L=0.1 m

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