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Q.

A bar magnet of magnetic moment 3.0 Am2 is placed in a uniform magnetic induction field of 2 x 10-5 T. If each pole of the magnet experiences a force of 6 x 10-4N. The length of the magnet is

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a

0.5 m

b

0.3 m

c

0.2 m

d

0.1 m

answer is D.

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Detailed Solution

F=mB⇒F=MLx B⇒6 x 10-4=3 L x 2 x 10-5 ⇒L=0.1 m
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