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A bar magnet of magnetic moment 104J/T is free to rotate in a horizontal plane. The work done in rotating the magnet slowly from a direction parallel to a horizontal magnetic field of 4 x10-5 T to a direction 600 from the field will be

0.2 J
2.0 J
4.18 J
2 x 102 J

detailed solution

Correct option is A

Magnetic moment of bar,  M=104 J/THence, work done, W=MB(cos 0 - cos 60)                                    = MB2                                   =104 x 4 x l0-5 x cos60o = 0.2 J

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