A bar magnet of magnetic moment 104J/T is free to rotate in a horizontal plane. The work done in rotating the magnet slowly from a direction parallel to a horizontal magnetic field of 4 x10-5 T to a direction 600 from the field will be
see full answer
High-Paying Jobs That Even AI Can’t Replace — Through JEE/NEET
🎯 Hear from the experts why preparing for JEE/NEET today sets you up for future-proof, high-income careers tomorrow.
An Intiative by Sri Chaitanya
a
0.2 J
b
2.0 J
c
4.18 J
d
2 x 102 J
answer is A.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
Magnetic moment of bar, M=104 J/THence, work done, W=MB(cos 0 - cos 60) = MB2 =104 x 4 x l0-5 x cos60o = 0.2 J