First slide

Magnetism

Question

A bar magnet of magnetic moment ‘M’ is freely suspended in a uniform magnetic field of strength ‘B’. The work done in rotating the magnet through angle $θ$ is

Moderate

A

$M B (1 - \cos θ)$
B

$M B \sin θ$
C

$M B \cos θ$
D

$M B$

Solution

The amount of work done to rotate the magnet from $θ_{1}$ and $θ_{2}$
$W = M B (\cos θ_{1} - \cos θ_{2}) P u t θ_{1} = 0^{0}, θ_{2} = θ \Rightarrow W = M B (1 - \cos θ)$

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