Q.
A bar magnet of magnetic moment M→ is placed in a magnetic field of induction B→. The torque exerted on it is
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a
M→.B →
b
-M→.B →
c
M→×B →
d
B →×M→
answer is C.
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Detailed Solution
TORQUE acting on a bar magnet when suspended in a uniform magnetic field is τ→=M→XB→
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