First slide

Magnetic dipole in a uniform magnetic field

Question

A bar magnet suspended in a field of induction 1.5 × 10^–6 T has a time period $\frac{π}{5}$ sec The moment of inertia about the axis of suspension is 1.5×10^–4 kgm². The magnetic moment of the magnet is

Moderate

Solution

$\begin{array}{rcl} T & = & 2 π \sqrt{\frac{I}{MB}} \\ \frac{π}{5} & = & 2 π \sqrt{\frac{1.5 x 10^{- 4}}{M x 1.5 x 10^{- 6}}}, \\ M & = & 10000 A - m^{2} \end{array}$

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