First slide

The bar magnet

Question

A bar magnet when placed at an angle of 30⁰ to the direction of magnetic field induction of 5×10^–5 T, experiences a moment of couple 2.5 × 10^–6 N–m. If the length of the magnet is 5 cm its pole strength is

Moderate

Solution

$\begin{array}{rcl} M & = & \frac{τ}{Bsinθ} = \frac{2.5 x 10^{- 6}}{5 x 10^{- 5} x \frac{1}{2}} = \frac{5 x 10^{- 6}}{5 x 10^{- 5}} = 10^{- 1} \\ m & = & \frac{M}{2 l} = \frac{10^{- 1}}{5 x 10^{- 2}} = 2 Am \end{array}$

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