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Q.

A bar magnet when placed at an angle of 300 to the direction of magnetic field induction of 5×10–5 T, experiences a moment of couple 2.5 × 10–6 N–m. If the length of the magnet is 5 cm its pole strength is

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answer is 3.

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Detailed Solution

M=τBsinθ=2.5 x 10-65 x 10-5 x 12=5 x 10-65 x 10-5=10-1m=M2l=10-15 x 10-2=2 Am
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