First slide
Second law
Question

A batsman deflects a ball by an angle of 600 without changing its initial speed of 20 ms–1. what is the impulse imparted to the ball if its mass is 0.15 kg?

Moderate
Solution

\large |\vec p_i|=|\vec p_f|=p
\large |\Delta\vec p_i|= Magnitude of change of momentum
= 2psinθ/2 = 2mvsinθ/2
\large \therefore Impulse = change in momentum
= 2 x 0.15 x 20 x sin300
=3 N-S

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