A batsman hits back a ball straight in the direction of the bowler without changing its initial speed of 12 ms-1.If the mass of the ball is 0.15 kg, the impulse imparted to the ball is

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1.5 Ns

3.6 Ns

7.2 Ns

10.2 Ns

answer is B.

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Detailed Solution

Change in momentum =mΔvGiven,m = 0.15 kg,Δp=0.15×12-(-0.15×12)Δp=3.6 N sIn the direction from the batsman to the bowler.

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