Download the app

current density

Question

A battery of emf E is connected across a conductor as shown. As one observes from A to B,

 Column-I Column-II
(i)current(p)increases
(ii)drift velocity of electron(q)decreases
(iii)electric field(r)remains same
(iv)potential drop per unit length(s)cannot be determined

Now, match the given columns and select the correct option from the codes given below.

Moderate
Solution

Current through any cross-section should remain same as all the cross-sections are in series.

I=neAvd, area increases drift velocity decreases. E is directly proportional to vd, so E also decreases. lf E decreases, then potential difference across a segment of fixed length also decreases.
This can also be done like this:

dR=ρdxA;  A  increases  with  x.Potential  across  dx:  dV=  IdR=IρdxAE=dVdx=A  1A

So E and dVdx both decrease as A increases.



Talk to our academic expert!

+91

Are you a Sri Chaitanya student?



Similar Questions

Electrons emerge from an electron accelerator as a beam having a circular cross-section of diameter 3 mm. The beam current is 6 μA and electrons are travelling so fast that their speed can be taken as c = 3 x 108 m/sec with an insignificant error. Electron density in the beam is :


phone icon
whats app icon