First slide

Thermal effect of current

Question

A battery of 3.0 V is connected to a resistor dissipating 0.5 W of power. If the terminal voltage of the battery is 2.5 V, the power dissipated within the internal resistance is :

Easy

A

0.072 W
B

0.50 W
C

0.125 W
D

0.10 W

Solution

Given,
$ε = 3 V$
Terminal potential difference = 2.5 V

The same potential difference is across external load $" R " = V_{R} = 2.5 V$
So $i = \frac{P_{R}}{V_{R}} = \frac{0.5}{2.5} = 0.2 A$
So power supplied $= ε i = 3 (0.2) = 0.6 W$
Hence power dissipated in $r = 0.6 - 0.5 = 0.1 W$

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