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A battery of 6 volts is connected to the terminals of a three metre long wire of uniform thickness and resistance of the order of 100 Ω The difference of potential between two points separated by 50 cm on the wire will be

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a

1 V

b

1.5 V

c

2 V

d

3 V

answer is A.

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Detailed Solution

Here same current is passing throughout the length of the wire, hence V ∝ R ∝ l⇒ V1V2 = l1l2 ⇒ 6V2= 30050 ⇒ V2=1 V

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