BC is divided into four equal parts by P, Q and R. The resultant of AB→ and 3 AC→ is

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AR→

4AR→

4AP→

PQ→

answer is B.

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Detailed Solution

AC→+CB→=AB→; AC→+4CR→=AB→AC→+4(AR→-AC→)=AB→;4AR→-3AC→=AB→∴AB→+3AC→=4AR→

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