A beaker containing a liquid of density ρ moves up with an acceleration a. The pressure due to the liquid at a depth h below the free surface of the liquid is
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a
hρg
b
hρ(g-a)
c
hρ(g+a)
d
2 hρgg+ag-a
answer is C.
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Detailed Solution
When a beaker containing a liquid of density ρ moves up with an acceleration a, it will work as a lift moving upward with acceleration a. The effective acceleration due to gravity in lift =(a+g)∴ Pressure of liquid of height h=hρ(a+g)