Q.

A beaker containing a liquid of density ρ  moves up with an acceleration a. The pressure due to the liquid at a depth h below the free surface of the liquid is

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a

hρg

b

hρ(g−a)

c

hρ(g+a)

d

2hρg(g+ag−a)

answer is C.

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Detailed Solution

When a beaker containing a liquid of density ρ  moves up with an acceleration a, it will work as a lift moving upward with acceleration a. The effective acceleration due to gravity in lift = (a + g) ∴  Pressure of liquid of height h=hρ(a+g)
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A beaker containing a liquid of density ρ  moves up with an acceleration a. The pressure due to the liquid at a depth h below the free surface of the liquid is