Q.

A beaker containing water weighs 100 g. It is placed on the pan of a balance and a piece of metal weighing 70 g and having a volume of 10 cm3 is placed inside  water in the beaker. The weight of the beaker and the metal would be:

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a

170 g

b

160 g

c

100 g

d

30 g

answer is A.

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Detailed Solution

Archimedes principle states that loss in weight of the body = weight of the volume displaced by it so we can easily say that Weight of the beaker and the metal = 170gm
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