A beaker contains 200 g of water. The heat capacity of the beaker is equal to that of 20 g of water. The initial temperature of water in the beaker is 20oC. If 440 g of hot water at 92oC is poured in it, the final temperature (neglecting radiation loss) will be nearest to

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58∘C

68∘C

73∘C

78∘C

answer is B.

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Detailed Solution

Heat lost by hot water = Heat gained by cold water in beaker + Heat absorbed by beaker⇒ 440(92−T)=200×(T−20)+20×(T−20)⇒ T=68∘C

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