A beam of ions with velocit5r 2x105 m/sec enters normally into a uniform magnetic field of 4 x10-2tesla. If the specific charge of the ion is 5 x 107 C/kg, the radius of the circular path described will be
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a
0.10 m
b
0.16m
c
0.20m
d
0.25m
answer is A.
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Detailed Solution
q0Br=mv or r=mvq0B∴ r=VBq0/m=2×10−54×10−25×107=0⋅10m