A beam of light from a source L is incident normally on a plane mirror fixed at a certain distance x from the source. The beam is reflected back as a spot on a scale placed just above the source L. When the mirror is rotated through a small angle θ the spot of the light is found to move through a distance y on the scale. The angle θ is given by

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x2y

y2x

answer is D.

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Detailed Solution

When mirror is rotated by θ angle reflected ray will be rotated by 2 θ.For small angle θ tan2θ≈2θ=yx∴ θ=y2x

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