A beam of light is incident on a liquid of  1.40  refractive index. The reflected rays are completely polarized. What is the angle of refraction of the beam? given tan54.40= 1.40

Refractive index of liquid μ=1.40 Angle of refraction ,r=900−θpWhere θp  is the polarizing angle, it is given by        tanθp=μ  θp=tan−1(μ)r=900−tan−1(μ)   =900−tan−1(1.40)  =900−54.40∴  r=35.60